Remove all emply folders in 1 command

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Written by pirat9 | 21 October 2009
Posted in Linux tutorials - Frequently Asked Questions

Q : How to remove all emply folders from command line ?

A : There is a good way to remove all emply folders in 1 command , everything will be done using a script so please copy the script bellow to a file with name script then make it executable : +x

chmod +x script

then execute the script with

./script  path

the script will give you the choice to edit and the approuve the folders found before removing

#!/bin/bash   
#Author : Mohamed Clay   
clear   
echo By : Mohamed clay   
echo   
if [ $# = 1 ]   
then   
 touch My_Empty_Directories   
 echo > My_Empty_Directories   
 echo The directories below are empty : >> My_Empty_Directories   
 echo >> My_Empty_Directories   
for name in `ls -p $1 | grep /`   
do   
 ls -l $1$name | grep 'total 0'   
 if [ $? = 0 ]   
 then   
 ls -l $1$name | grep d   
 if [ $? = 1 ]   
 then   
 hide=`ls -al $1$name | grep . | wc -l`  
 if [ $hide != 4 ]  
 then  
 echo $1$name >> My_Empty_Directories   
 fi   
 fi   
 fi  
done   
 line=`cat My_Empty_Directories | wc -l` 
 if [ $line = 3 ] 
 then 
 echo 
 echo No empty directorie has been found 
 echo 
 rm -rf My_Empty_Directories 
 else  
 cat My_Empty_Directories  
 echo 'Do you want to delete them (yes/no/edit):'   
 read answer    
 if [ $answer = yes ]   
 then   
 rm -rf `cat My_Empty_Directories`   
 rm -rf My_Empty_Directories   
 echo Successfully done   
 fi   
 if [ $answer = edit ]   
 then   
 nano My_Empty_Directories   
 rm -rf `cat My_Empty_Directories`   
 rm -rf My_Empty_Directories   
 echo Successfully done   
 else   
 rm -rf My_Empty_Directories   
 fi 
 fi   
 else   
 echo Usage : ./script PATH   
 fi   
#END